(Q4).If x2 + y2 = 6xy, prove that 2 log (x + y) = log x + log y + 3 log 2

x2 + y2 = 6xy

(x + y)2 - xy = 6xy

(x + y)2 = 6xy + xy

(x + y)2 = xy

log (x + y)2 = log xy

2 log (x + y) = log + log x + log y

2 log (x + y) = log 3 + log x + log y

2 log (x + y) = log 2 + log x + log y

Hence Proved