(Q6).Find the HCF of 1.2 and 0.12 using Euclid's algorithm ?

Given: 1.2 and 0.12

we have 1.2 =
=
0.12 =

Now considering the numerators 12 and 120, their HCF is .

∴ HCF of 1.2 and 0.12 is
=

i.e., if x is a factor of y then x is the HCF of x and y.