In order to check whether 6n can end with the digit 0 for any natural number n, let us find the factors od 6.
It's seen that the factors of 6 are 2 and .
So, 6n=(×3)n
6n = n × 3n
Since, The prime factorization of 6 does not contain 5 and 2 as its factor, together. We can thus conclude that 6n can never end with the digit 0 for any natural number n.