(Q5). Find the HCF and LCF of the following given pairs of numbers by prime factorisation method 120,90.

HCF of numbers = Product of the smallest power of each common - prime factors of the number

LCM of numbers = Product of greatest power of each prime factors of the number.

120 = ×2×2×3×5

= 3×3×5

90 = 2××3×5

= 2×2×5

HCF = 2 × 3 × 5 =

LCM = 23 × 32 × 5 =

HCF =

LCM =