(Q6). Find the HCF and LCF of the following given pairs of numbers by prime factorisation method 50,60.

HCF of numbers = Product of the smallest power of each common - prime factors of the number

LCM of numbers = Product of greatest power of each prime factors of the number.

50 = 2×5×

= 2×2

60 = ×2×3×5

=2×3×5

HCF = 2 × 5 =

LCM = 22 × 3 × 52 =

HCF =

LCM =