(Q4).Show that 3√2 is irrational .

3√2

Let us assume that 3√2 is rational.

That is, we can find co-primes a and b (b ≠ 0) such that 3√2 =
a
b
We get √2 =
a
3b
Since 3, a and b are integere,
a
3b
 is rational, and √2 is also .

But this contradicts that fact that √2 is .

This contradiction has arisen because of our assumption that 3√2 is .

So 3√2 is