(Q41).Using loga xn = nloga x, expand log 523

Note: log x = log10x

log 523

log10 523

log10 5

written as per the given formula

23log10 5 = 23
log5
log
23 log10 5 = 23
log5
log(5×)
23
log5
log(5×2)
= 23
log5
log5 + log

So it is

23
log5
log5 + log