(Q47).We know that, if 7 = 2x then x = log27, what is the value of 2log2 7 ? Justify your answer. Generalize the above by taking some more examples for aloga N.

if 7 = 2x then x = log27

2log2 7

2log2 7 = 2x

= 2x = 7

Example :i

3 = 6x

X = log6

X = log6 = 6x =

Example :ii

5 = 3x

X = log3

3log3 = 3x =

alogan = n

If a values are equal, n value will be the answer.

verified

So it is 2log2 7 =