(Q49).Write 2log3 + 3log5 - 5log2 as single logarithm

2log3 + 3log5 - 5log2

= log32 + log53 - log25

= log9 + log125 - log32

= log (9 × ) - log32

= log - log32

=Log
32
2log3 + 3log5 - 5log2 = Log
32

So it is

2log3 + 3log5 - 5log2 = Log
32