(Q11) Consider a triangle △PQR,right angled at R ,in which PQ=29cm units,QR=21cm units ∠PQR =θ,then find the values of
(i)cos2θ+sin2θ(ii)cos2θ-sin2θ

RPQ

PR2=

PR=units

sin θ=
PR
PQ
=

cos θ=
QR
PQ
=
Now (i)cos2θ+sin2θ=
PR2
PQ2
+
QR2
PQ2
=

(ii)cos2θ-sin2θ=
PR2
PQ2
-
QR2
PQ2
=