(Q13)The sides of right angled triangle PQR and PQ=7Cm,PR=25cm and ∠Q=90°respectively.Then find,tan P- tan R
P
Q
R
7cm
25cm
Solution:
In triangle PQR using pythagoras theorem
Given:
PQ=7Cm,PR=25cm and ∠Q=90°
PR
2
=PQ
2
+QR
2
QR
2
=
QR=
cm
tan P=
adjacent
opposite
=
tan R=
opposite
adjacent
=
tan P-tan R=
clear