(Q6)In a triangle △PQR,with right angle at Q,the value of ∠p is x,PQ=7cm and QR=24cm,then find sinx and cosx.

Given:

△PQR,with right angle at Q,the value of ∠p is x,PQ=7cm and QR=24cm

Solution:

using Pythagoras theorem

PR2=PQ2+QR2

PR2=

PR=

(i)sin X=
opposite side
hypotenuse
=

(ii) cos X=
adjacent
hypotenuse
=