(Q7)In a right angled triangle △ABC,right angle is at C.BC+CA=23cm and BC-CA=7cm,then find sin A and tan B

Given:

BC+CA=23cm

BC-CA=7cm

To find:

The value of sin A and tan B

Solution:

According to the question,

BC+CA=23cm -------equation 1

BC-CA=7cm --------equation 2

Adding these two equations,we will get

2BC=cm

BC=cm

putting the value of BC in equation 1,

BC+CA=23cm -------equation 1

+CA=23cm

CA=cm

using the Pythagoras theorem in △ABC,

AB²=BC²+CA²

AB²=²+ ²

AB=cm

so,for angle A,

The perpendicular will be BC and the hypotenuse will be AB.

we know that sin is perpendicular /hypotenuse

therefore,

For angle B,

The perpendicular will be CA and the base will be BC

therefore,