(Q12)If sin (A - B) =
1
2
, cos(A+B) =
1
2
, where 0° < A+B ≤ 90° and A>B,find A and B.

Since sin(A-B) =
1
2
, therefore, A-B = ° (why?)
Also, since cos(A+B) =
1
2
, therefore, A+B = ° (why?)

Solving the above equations, we get : A = ° and B = °.(How?)