(Q12)
If sin (A - B) =
1
2
, cos(A+B) =
1
2
, where 0° < A+B ≤ 90° and A>B,find A and B.
Since sin(A-B) =
1
2
, therefore, A-B =
° (why?)
Also, since cos(A+B) =
1
2
, therefore, A+B =
° (why?)
Solving the above equations, we get : A =
° and B =
°.(How?)
Clear