(Q2)Check and discuss the above relations in the case of angles between 0° and 90°,whether they hold for these angles or not?So,

(i)sin(90°-A)=cos A (ii)cos(90°-A)=sin A (iii)tan(90°-A)=cot A (iv)cot(90°-A)=tan A (v)sec(90°-A)=cosc A
(vi)cosec(90°-A)=sec A

Answer:

Let A=30°

(i)sin(90°-A)=cos A
sin(90°-30°)
sin 60°=cos 30°
cos 30°=

√

(ii)cos(90°-A)=sin A
cos(90°-30°)
cos 60°=sin 30°
sin 30°=

(iii)tan(90°-A)=cot A
tan(90°-30°)
tan 60°=cot 30°
cot 30°= √

(iv)cot(90°-A)=tan A
cot(90°-30°)
cot 60°=tan °
tan 30°=

√

(v)sec(90°-A)=cosec A
sec(90°-30°)
sec 60°=cosec 30°
cosec 30°=

(vi)cosec(90°-A)=sec A
cosec(90°-30°)
cosec 60°=sec 30°
sec 30°=

√