(Q4)If cos 7A=sin(A-6°),where 7A is an acute angle,find the value of A

Answer:

Given cos 7A=sin (A-6°)

sin(-7A)=sin(A-6°)

since (-7A)&(A-6°)are both a acute angles,

therefore

°-7A=A-6°

8A=°

A=°