(Q11)Evaluate the following:

i. (1 + tan θ + sec θ) (1 + cot θ – cosec θ)

Given (1 + tan θ + sec θ) (1 + cot θ – cosec θ)

= (
1
1
+
θ
θ
+
1
θ
)(
1
1
+
θ
θ
-
1
θ
)
= (
(θ + θ) + 1
θ
)(
(θ + θ) - 1
θ
)
=
(θ + θ)2 - ()2
θ.θ
[∵(a + b)(a - b) = a2 - b2]
=
2θ + 2θ + 2 sinθ cosθ - 1
θ.θ
[∵(a + b)2 = a2 + b2 + 2ab]
=
+ 2 sin θ . cos θ - 1
θ . θ
[∵ cos2 θ + sin2 θ = 1]
=
sinθ . cosθ
θ . θ
=