(Q13)Evaluate the following:

iii. (sec2 θ – 1) (cosec2 θ – 1)

Given (sec2 θ – 1) (cosec2 θ – 1)

= 2 θ × 2 θ [∵ sec2 θ – tan2 θ = 1; cosec2 θ – cot2 θ = 1]

= 2 θ ×
1
2 θ
=