(Q7)Evaluate the following and justify your answer.

sec 16° cosec 74° – cot 74° tan 16°.

Given sec 16° cosec 74° – cot 74° tan 16°

= sec 16° . cosec (° – 16°) – cot (° – 16°) . tan 16°

= sec 16°. sec ° – tan ° . tan 16° [∵ cosec (90° – θ) = sec θ; cot (90° – θ) — tan θ]

= sec2 ° – tan2 °

= [∵ sec2 θ - tan2 θ = 1]