(Q4) An iron spherical ball of volume 232848 cm3 has been melted and converted into a cone with the vertical angle of 120o. What are its height and base?

Solution :

In the right angled triangle BOA

r
h
 = tan 60°
r
h
 = √

r = √h

Now as sphere is melted and converted into a cone

Volume of sphere = Volume of cone

232848 =
1
 π 2
232848 × =
22
7
 (h2)
h3 =
x 232848

h3 = x

h3 = 7 x 7 x x 6 x 6 x

h3 = 3 x 3

h3 = ( x )3

h = x

height h =

base r = √3 = √3 x = 1.732 x =