(Q12)let p(x)=x2-4x+3.Find the values of p(0),p(1),p(2),p(3) and obtain zeros of the polynomial p(x)

Answer:

Given polynomial p(x)=x2-4x+3

p(0)=(0)2-4(0)+3=

p(1)=(1)2-4(1)+3=1-4+3=

p(2)=(2)2-4(2)+3=4-8+3=

p(3)=(3)2-4(3)+3=9-12+3=

we see that p() and p() are zeros of the polynomial p(x).