(Q2) Find the number of zeros of the given polynomials and also find the values
(i)p(x)=2x+1 (ii)q(y)=y2 - 1

Solution:

(i)p(x)=2x+1 is a linear polynomial. It has only one zero

to find zeros,

Let p(x)=0

so,2x+1=0

therefore x =
the zero of the given polynomial is =

(ii)q(y)=y2-1 is quadratic polynomial

It has most two zeros

to find zeros,let q(y)=0

y2 - 1=0

(y+) (y-)=0

y=or y=

therefore the zeros of the polynomial are and