(i)Given polynomial is y= - x3
f(x)= - x3;f(x)=0
x3=
x=
Zero of the polynomial f(x) is only one i.e,.
(ii)Given that y=x2 - x3
f(x)=x2(1-x)
f(x)=0
x2(-x)=0
x2=0 and -x=0
x=0 and x=
The zeros of the polynomial f(x) are two 0 and .
(iii)Given that x3 - 5x2+6x
Let f(x)=x3 - 5x2+6x
x(x2 - 5x+6)
x(x2 -x-3x+6)
x[x(x-) - 3(x-)]
x(x-)(x-3)
The zeros of the polynomial f(x) are x=0 and x= and x=3.