Answer

Given polynomial p(x)=x²+3x-4

List of values of p(x):

x	-4	-3	-2	-1	0	1	2
x2
3x	-	-	-	-
x2+3x			-	-
4
p(x)		-	-	-	-
(x,y)	(-,)	(-,-)	(-,-)	(-,-)	(,-)	(,)	(,)

Now,lets locate the points listed above on a graph paper,

Result: We observe that the graph cuts the X -axis at(-4,0) and (1,0).

So, the zeros of the polynomial are -4 and 1.

Justification:

Given p(x)=x²+3x-4=0

x²+x-x-4=0

x(x+)-1(x+)=0

(x+)(x-)=0

x+=0 and x-=0

x=- and x=