Given polynomial p(x) = x2 - 1
List of the values of p(x):
x | -2 | -1 | 0 | 1 | 2 |
x2 | |||||
1 | |||||
p(x) | - | ||||
(x,y) | (-,) | (-,) | (,-) | (,) | (,) |
Now lets locate the points listed above on a graph paper and draw the graph,
Result: We observe that the graph cuts the X-axis at (-1,0) and (1,0).
So the zeros of the polynomial are 1 and 1.
Justification:
p(x) = (x+) (x-) = 0
x+ = 0 and x- = 0
x = -and x =