(i)Given polynomial p(x)=x2 - x -6
We have x2 - x -6=x2 - 3x+ x-6
= x(x- )+ (x-3)
=(x-3)(x+2)
So,the value of x2 - x-6 is zero when x- =0 or x+ =0
x= or x= -
So,the zeros of x2 - x -6 are and -
Sum of the zeros = - =
Product of the zeros = ×(- ) = -6
=