Given polynomial is x2-2x-8
where have x2-2x-8=x2- x+2x-8
=x(x-)+2(x-)
(x - )(x+2)
so, the value of x2-2x-8 is zero
when x - =0 or x+2=0
when x= or x=-2
So,the zeros of x2-2x-8 are and -2
Sum of the zeros=-2=
Sum of Zeros = 4 - (-)
And product of the zeros =×(-2)= -