(Q14)Find the zeros of the following quadratic polynomials and verify the relationship between the zeros and the coefficients 6x2-3-7x.

Answer:

Given polynomial is 6x2-3-7x

We have,6x2-3-7x=6x2-7x-3

=6x2-x+2x-3

=3x(x-3)+(2x-3)

=(x-3)(3x+)

The value of 6x2-3-7x is zero,when the value of(3x+)(x-3)is 0

when 3x+=0 and x-3=0

3x= - and x=3

x=
-
3
 and x=
3

the zeros of 6x2-3-7x=
-
3
 and
3

sum of zeros=
3
 +
3
 =
6

= -
coefficient of x
coefficient of x2
 =
-(-)
6
 =
6

And product of the zeros =(
-
3
)×(
3
)=
-1
=
constant term
coefficient of x2
 =
-
6
 =
-1