(Q15)Find the zeros of the following quadratic polynomials and verify the relationship between the zeros and the coefficients 4u2+8u.

Answer:

Given polynomial is 4u2+8u

we have,4u2+8u=4u(u+)

the value of 4u2+8u is 0,

When the value of 4u(u+)=0

when u=0 or u+=0

when u=0 or u=-

the zeros of 4u2+8u are 0 and -

therefore,sum of the zeros =0+(-)= -

= -
coefficient of u
coefficient of u2
 =
-
 = -

product of the zeros 0,(-)=0
=
constant term
constant term of u2
 =
=