Answer:

Given polynomial is t²-15

we have,t²-15=(t-√)(t+√15)

the value of t²-15 is 0

when the value of (t-√)(t+√15)=0

when t-√=0 or t+√15=0

when t=√ or t=-√15

the zeros of t²-15 are √ and -√15

therefore sum of the zeros =√+(-√15)=

product of tbe zeros √×(-√15+)= -