Given polynomial p(x)=x2-4x+3
We have,x2-4x+3=x2- x-x+3
=x(x- )-1(x- )
=(x- )(x-1)
So, the value of x2-4x+3 is zero
when x- =0 or x-1=0
when x= or x=1 so, the zeros of x2-4x+3 are and 1
sum of the zeros = +1=
And product of the zeros = ×1=