(Q5)Find the zeros of the quadratic polynomial x2+7x+10, and verify the relationship between the zeros and the coefficients.

We have

x2+7x+10=(x+ )(x+5)

So,the value of x2+7x+10 is zero when x+ =0 or x+5=0,

when x= - or x= -5

Therefore, the zeros of x2+7x+10 are - and -5.

Now,sum of the zeros = - +(-5)= -( )=
-
1
 =
-(coefficient of x)
coefficient of x2
product of the zeros = - ×(-5)= =
1
 =
constant term
coefficient of x2