(Q6)Find the zeros of the polynomial x2-3 and verify the relationship between the zeros and coefficients.

Answer:

Recall the identity a2-b2 =(a-b)(a+b).

Using it,we can write:

x2-3=(x-√)(x+√3)

so, the value of x2-3 is zero when x=√ or x= - √3

Therefore,the zeros of x2-3 are √ and -√3

sum of the zeros =√+(-√3)= =
-(coefficient of x)
coefficient of x2

product of zeros =(√)×(-√3)=- =
-
1
 =
constant term
coefficient of x2