(Q4)Find all the zeros of 2x4-3x3-3x2+6x-2,If you know that two of its zeros are √2 and -√2

x2-x+

x2-2) x4-x3-x2+x-
x4    -x2
-       +

-x3+2+x-
-x3    +x
+      -

2 -
2 -
-  +

So,2x4-3x3-3x2+6x-2=(x2-2)(x2-x+)

Now, by splitting -x, we factorize 2x2-3x+1 as(x-1)(x-1).So, its zeros are given by x=
1
and x=1. Therefore, the zeros of the given polynomial are √2 and -√2, 1 and
1