(Q4). Solve the given equation.

√3x + √2y = √3

√5x + √3y= √3

Given that √3x + √2y = √3 …… (1)

√5x + √3y = √3 …… (2)

By following elimination method

eqn. (1) × √ ⇒   x + √y =  
eqn. (2) × √ ⇒ √x + √y = √
(-) (-) (-)

(-√)x = - √

x =
- √
- √

Now again following elimination method

eqn. (1) × √ ⇒ √x + √y = √
eqn. (2) × √ ⇒ √x +  y  =  
(-) (-) (-)

(√-)y = - + √

-(-√)y = -(-√)

y =
- √
- √
∴ The solution x =
-√
-√
 and y =
-√
-√