(Q.11). Two rails of a railway track are represented by the equations. x + 2y – 4 = 0 and 2x + 4y – 12 = 0. Represent this situation graphically.

x + 2y – 4 = 0

2y = – x

y =
- x
2x – y = 4
x y =
4 - x
2
 		(x,y)
0 (0,)
4 (4,)
2 (2,)
6 - (6,-)

2x + 4y – 12 = 0

4y = 12 – x

y =
6 - x
2x + 4y – 12 = 0
x y =
6 - x
2
 		(x,y)
0 (0,)
2 (2,)
6 (6,)

These lines are and hence no solution.