Let the number of bees = x and
the number of flowers = y
If one bee sits on each flower then one bee will be left. So, x = + 1
or x - y - = 0 ... (1)
If two bees sit on each flower, one flower will be left. So, x = 2(- 1)
or x - 2y + = 0 ... (2)
| For the equation x - y - 1 = 0 | ||
|---|---|---|
| x | y = x - 1 | (x,y) |
| 0 | y = - 1 = - | (0,-) |
| 1 | y = - 1 = | (1,) |
| 2 | y = - 1 = | (2,) |
| 3 | y = - 1 = | (3,) |
| 4 | y = - 1 = | (4,) |
| For the equation x - 2y + 2 = 0 | ||
|---|---|---|
| x |
y =
x + 2
2
|
(x,y) |
| 0 |
y =
+ 2
2
=
|
(0,) |
| 2 |
y =
+ 2
2
=
|
(2,) |
| 4 |
y =
+ 2
2
=
|
(4,) |
| 6 |
y =
+ 2
2
=
|
(6,) |
In the graph, (, ) is the point of intersection. Therefore, there are bees and flowers