(Q.39) Half the perimeter of a rectangular garden, whose length is 4 m more than its width is 36 m. Find the dimensions of the garden.

Let the width of the garden = x cm

then its length = x + cm

Half the perimeter =
× 2(l+ b) = l + b

By problem, x + x + = 36

2x + = 36

2x = 36 – =

∴ x = and x + 4 = + 4 =

i.e., length = cm and breadth = cm.