(Q12).Solve the given pair of linear equations, (a – b)x + (a + b)y = a2 – 2ab – b2,(a + b) (x + y) = a2 + b2

(a – b)x + (a + b)y = a2 – 2ab – b2

(a + b)x + (a + b)y = a2 + b2

x[a--a-] = -ab -b2 ⇒ -b(a+b)

x(-b) = – b(a + b)

⇒ x = ( + )

Put this value of ‘x’ in eq (1) we get

(a – b) (a + b) + (a + b)y = a2 – 2ab – b2

2 – 2 + (a + b)y = 2 – ab – 2

⇒ y =
-ab
+
∴ Solution to given pair of linear equations x = a + b, y =
-ab
+