Let the number of ₹50 notes be x;
Let the number of ₹100 notes be y;
then, x + y = ...............(1)
and x + y = ...........(2)
Solutions through the substitution method:
From equation (1) ⇒ x = -
Substituting in equation (2) ⇒ 50 ( - ) + 100y = 2000
- y + 100y = 2000
50y = 2000 - =
x = - =
Hence, Rubina received ₹50 notes and ₹100 notes.
Solution through the elimination method:
In the equations, coefficients of x are 1 and 50 respectively. So,
-y = -
Substitute y in equation (1) x + = 25
x = 25 - =
Hence Rubina received ₹50 notes and ₹100 rupee notes.