Let the numerator of the fraction = x
and the denominator of the fraction = y
By problem,
⇒ (x + 1) = (y + 1) and (x – 5) = (y – 5)
x + = y + and x – = y –
⇒ x – y = – and x – y = – +
⇒ x – y = – …… (1)
and x – y = …… (2)
Substituting y = in equation (2) we get
2x – = 5
⇒ 2x = 5 +
⇒ 2x = and