(Q6).Solve each pair of equations by using the substitution method.

0.2x + 0.3y =1.3

0.4x + 0.5y = 2.3

Given:

0.2x + 0.3y = 1.3

⇒ 2x + 3y = 13 …… (1)

0.4x + 0.5y = 2.3

⇒ 4x + 5y = 23 …… (2)

From equation (1)

2x = – y

⇒ x =
- y
Substituting x =
- y
 equation (2) we get
- y
 + 5y = 23

⇒ – y + 5y = 23

⇒ -y + = 23

⇒ y = — 23 =

Substituting y = in equaion (1) we get

2x + 3() = 13

⇒ 2x + = 13

⇒ 2x = 13 –

⇒ 2x =

⇒ x =
2
 =

∴ The solution is (, )