Given:

√2x + √3y = 0 ……. (1)

√3x – √8y = 0 ……. (2)

Substitute x = in (1),

√2() + √3y = 0

√3y = 0

∴ y =

∴ The solution is x = , y =

Note: a₁x + b₁y + c₁ = 0

a₂x + b₂y + c₂ = 0, if c₁ = c₂ = 0

then, x = , y = is a solution.