3x + 2y = 11 ...........(1)
2x + 3y = 4 ............(2)
Let us eliminate 'y' from the given equations. The coefficients of 'y' in the given equations are 2 and 3. L.C.M.of 2 and 3 is 6. So, multiply equation (1) by 3 and equation (2) by 2.
Substitute x = , in equation (1)
3() + 2y = 11
Therefore, the required solution is x = , y = - .