(Q20)Find the roots of the following equations.
(i) x -
1
x
= 3, x ≠ 0
Answer:
Given: x -
1
x
= 3, x ≠ 0
x
2
+ 6x + 5 = 0
x
2
- 1
x
= 3
x
2
- 1 = 3x
x
2
- 3x - 1 = 0
Here a = 1; b = -3; c = -1
-b ± √(b
2
-4ac)
2a
=
-(-3) ± √ ((
)
2
-4(
)(-
))
2 × 1
=
3±√
+
2
=
3 ± √
2
∴ x =
3+√
2
or
3-√
2
clear