Let the first positive integer be x.Then, the second integer will be x + 2. According to the question,
x2(x + 2)2 = 290
x2 + x2 + 4x + 4 = 290
2x2 + 4x - 286 = 0
x2 + 2x - 143 = 0
which is a quadratic equation in x.
x = or x= -13
But x is given to be positive odd integer.Therefore,x≠ -13
Thus, the two consecutive odd integers are and (x+2)=+2=.
Check:2+2 = 121 + 169 = 290.