(Q8)Find the nature of the roots of the following quadratic equations.If real roots exist,find them.
(iii)2x2 - 6x + 3 = 0

Answer

Given 2x2 - 6x + 3 = 0

a = 2; b = -6; c = 3

b2 - 4ac

= (-6)2 - 4()()

= 36 -

= > 0

The roots are real and distinct.They are

-b + √(b2 - 4ac)
2a
 ,
-b - √(b2 - 4ac)
2a

-(-6) + √
2 × 2
 ,
-(-6)-√
2 × 2

6+2√
2×2
 ,
6 - 2√
2×2

3+√
2
 ,
3 - √
2