Given: a2 = a + d = ….. (1)
a4 = a + 3d = ….. (2)
Solving equations (1) and (2);
⇒ a + 3d =
⇒ a + d =
d = -
⇒ d = -
∴ Substituting d = – in equation (1) we get
a + (-) = 13
∴ a = 13 + = i.e., a1 =
a3 = a + 2d = + 2(-)
= – =