Given: An A.P. whose
3rd term = a + d = ......(1)
9th term = a + d = -.......(2)
-d =
Substituting d = - in equation (1) we get
a + × (-) =
⇒ a – =
⇒ a = + =
Let nth term of the given A.P be equal to zero.
an = a + (n – 1)d
⇒ = + (n – 1) × (-)
⇒ = – n +
⇒ – n =
∴ The th term of the given A.P is zero.