(Q22).The 17th term of an A.P exceeds its 10 term by 7. Find the common difference.

Given an A.P in which a17 = a10 + 7

⇒ a17 – a10 = 7

We know that an = a + (n – 1)d

a17 = a + d

a10 = a + d

-d =

⇒ d =
=